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Question :-
Gravitational force on the surface of the moon is only 1/6 as strong as gravitational force on the earth. What is the weight in newtons of a 10 kg object on the moon and on the earth?

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Answer 1

Answer:

Given;

Gravitational force on the surface of the moon = 1/6× Gravitational force on the surface of the Earth.

Therefore;

Weight on Moon = 1/6× Weight on Earth.

Finding Weight on Earth;

Mass of the object = m = 10kg.

Acceleration due to Gravity(G) = mg = 10×9.8 = 98N.

Therefore;

Weight on Moon = 1/6× Weight on Earth.

= 1/6× 98

= 16.33N.

Ans) The weight of object on earth is 98 N and on moon is 16.33 N respectively

Answer 2

${ \boxed{\boxed{ \begin{array}{cc} \bf \: \to \: given : \\ \\ \hookrightarrow \sf \:mass \: of \: the \: object \: \: m = 10 \: kg \\ \\ \pink{ \sf \: we \: have \: to \: find :} \\ \\ \hookrightarrow \sf \: weight \: of \: the \: object \: on \: earth = W_e \\ \\ \hookrightarrow \sf \:weight \: of \: the \: object \: on \: moon = W_m \\ \\ \\ \\ \red{ \underline{ \bf \: we \: know \: that : }} \\ \\ \sf W = mg \\ \\ \rm \: here \: \\ \\ \sf \:W = Weight \\ \\ \sf \: m= mass \: of \: object \\ \\ \sf \: g = acceleration \: due \: to \: gravity \\ \\ \bf \: we \: also \:know \:that : \\ \\ \hookrightarrow \sf \: For \: earth \: g_e= 9.8 \: ms^ {- 2} \\ \\ \hookrightarrow \sf \:For \: moon \: gravity \: is \:g_m = \frac{1}{6} \times gravity \: of \: earth \\ \\ \sf = \frac{1}{6} \times 9.8 = 1.63 \: m {s}^{ - 2} \\ \\ \\ \orange{ \boxed{\sf \: \therefore weight \: of \: the \: object \: on \: earth \: \: W_e = 10 × 9.8 = 98 \: N}} \\ \\ \\ \blue{ \boxed{\sf \: weight \: of \: the \: object \: on \: moon \: \: W_m =10 × 1.63 =16.3 \: N}}\end{array}}}}$