Question

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A shopkeeper bought 3 tables at Rs.250 each.He sold the first one at a profit of 20%,the second one at a loss of 16% and the third one was sold at such a price that his total profit was 15%.what was the selling price of the third table?​​

Answer 1

Given :-

The cost price of each table = Rs.250

Profit on 1st table by selling = 20%

Loss on 2nd table by selling = 16%

Profit on whole calculation = 15%

To Find :-

The selling price of 3rd table = ?

Solution :-

To calculate the selling price of 3rd table at, first we have to find out total cost price and selling price then setting up equation by applying formula. Before calculation , we have to assume the selling price of 3rd table P.

Calculation for 1st table :-

[Cost price = Rs.250. Profit = 20%]

⇒ SP = (100 + P%)/100 × CP

⇒ SP = (100 + 20)/100 × 250

⇒ SP = 120/100 × 250

⇒ SP = 12 × 25

⇒ SP = Rs.300

Calculation for 2nd table :-

[Cost price = Rs. 250. Loss = 16%]

⇒ SP = (100 - L%)/100 × CP

⇒ SP = (100 - 16)/100 × 250

⇒ SP = 84/100 × 250

⇒ SP = 21 × 10

⇒ SP = Rs.210

Calculation for 3rd table :-

[Cost price = Rs. 250. Selling price = P]

Calculation for total CP and SP :-

⇒ Total CP = Cost of 3 tables

⇒ Total CP = 250 × 3

⇒ Total CP = Rs. 750

⇒ Total SP = Selling of 3 tables

⇒ Total SP = SP(1st + 2nd + 3rd) tables

⇒ Total SP = 300 + 210 + P

⇒ Total SP = Rs.(510 + P)

By solving above we have here :-

[Total CP = Rs.750. Total SP = Rs. (510 + P). P = 15%]

⇒ SP = (100 + P%)/100 × CP

⇒ 510 + P = 115/100 × 750

⇒ 510 + P = 1.15 × 750

⇒ 510 + P = 862.5

⇒ P = 862.5 - 510

⇒ P = Rs. 352.5

Hence, the selling price of 3rd table (P) = Rs. 352.5 :-