Question

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$\huge\sf\pink{Question}$

D is a point on side BC of ΔABC such that ∠ABC > ∠ACB and AB > AD. Then, which of the following statement is always true? A)∠ACB > ∠ADC
B)∠ABC > ∠ADC
C)∠ACB < ∠ADC
D)∠ADB < ∠ABC​

$\sf\bold{explanation\: is\: must}$​

Answer 1

Answer:

Given:AD=AC

Angles opposite to equal sides are equal

So, ∠ACD=∠ADC .......(1)

Now, ∠ADC is an exterior angle of △ABD

∠ADC=∠ABD+∠BAD since exterior angle is sum of interior opposite angles.

So, ∠ADC>∠ABD

⇒∠ACD>∠ABD since side opposite to the greater angle is longer

∴AB>AD as AC=AD given

Hence proved.

Step-by-step explanation:

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