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If AB = QR, AC = PQ and BC = PR, then
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they are congruent by SAS conference of triangle so, ABC ≈ QRP
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△ABC∼△QRP
Given △ABC∼△QRP
Therefore, Area△QRPArea△ABC=PR2BC2
or 49=PR2152
or PR2=9152×4cm
Therefore, PR=315×2= 10cm.
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