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Length of a rectangle is twice its breadth and its perimeter is 70cm .Find the area .


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Answer 1

Let the breadth of the rectangle be xcm

Then it's length=x+5cm

Perimeter=2(length+breadth)

⇒70=2(x+(x+5))

⇒

2

70

=2x+5

⇒2x+5=35

⇒2x=35−5=30

⇒x=

2

30

=15cm

Breadth=x=15cm and length=x+5=15+5=20cm

Answer 2

Question:-

Length of a rectangle is twice its breadth and its perimeter is 70cm .Find the area .

Required Answer:-

Given:-

• Leng6of a rectangle is twice of the breadth.
• Perimeter of the rectangle is 70cm

To Find:-

• Area of the rectangle.

Solution:-

Let,

• Breadth of the rectangle be x
• Hence, length of the rectangle = 2 × x = 2x

We know that,

• Perimeter of a Rectangle = 2(length+breadth)

We have,

• Breadth = x
• Length = 2x

According to the question,

2(x + 2x) = 70

=> 2 × 3x = 70

=> 6x = 70

=> x = 70/6

=> x = 11.67

Now,

• Breadth = 11.67cm
• Length = (2 × 11.67) cm = 23.33cn

We know that:-

• Area of Rectangle= Length × breadth

We have,

• Breadth = 11.67cm
• Length = 23.33cm

Hence,

➡ Area of the rectangle = (11.26 × 23.33)cm^2

➡ Area of the rectangle = 272.2611cm^2

Hence, area of the rectangle is 272.2611cm^2