Question

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❐Other best users ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ The external diameter of a 49-cm-long metal pipe is 26cm. If the pipe is 1 cm thick and the density ofthe metal is 9.8 g/cm^3, find the volume of the metal used in the pipe and the mass of the pipe. ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ Don't dare for spam !​

Answer 1

${\large{\bf{\underline{\underline{\purple{Given -]}}}}}}$

• Height [H] = 49 cm

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• Thickness of pipe = 3cm

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• Density of material = 9.8 cm³

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• External diameter = 26m

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• For finding radius

= 26/2 = 13

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• Internal Radius = r = External radius - thickness

r = 13 - 3 = 10cm

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firstly it is necessary to find the volume of pipe

Because it's require for solving question .

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${\large{\bf{\underline{\underline{\red{Formula \: Of \: Volume}}}}}}$

• Volume (V) = Effective area × height

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• Volume = π [R²-r²] × H

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${\large{\bf{\underline{\underline{\red{[V = ] \frac{22}{7} \times ( {13}^{2} - {10}^{2})\times 49 }}}}}}$

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• 22× [169-100]×7

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• = 3018

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• Now we Need To Find Out Mass Of Material Density Of Material is Given In Question

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${\large{\bf{\underline{\underline{\red{Mass = Density × Volume }}}}}}$

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• Mass = 9.8 × 3,018

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• Mass = 29,576.4

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Final Answer

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${\large{\bf{\underline{\underline{\purple{Mass = 29,576.4}}}}}}$