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Linear Equations in One Variable
A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. What are the numbers? Thus, the required numbers are 7 and 35
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Given :-
A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number.
To Find :-
Numbers
Solution :-
Let the positive number be a
5 times the positive number = 5a
21 added to both number
2(a + 21) = 5a + 21
2a + 42 = 5a + 21
2a - 5a = 21 - 42
-3a = -21
a = -21/-3
a = 21/3
a = 7
Therefore
Numbers are
a = 7
5a = 5(7) = 35
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