CBSE BOARD X, asked by shivasinghmohan629, 1 day ago

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Answered by BrainlyArnab
2

QUESTION :-

Find the zeroes of following quadratic polynomials and verify the relationship between the zeroes and coefficients.

4x² - x - 5

______________________

SOLUTION :-

4x² - x - 5

In the standard form of quadratic polynomial (ax² + bx + c), here -

  • a (coefficient of ) = 4
  • b (coefficient of x) = -1
  • c = -5

_____________________

First of all, we have to find the zeroes of polynomial.

4x² - x - 5 = 0

=> 4x² + 4x - 5x - 5 = 0

=> 4x(x + 1) -5(x + 1) = 0

=> (x + 1)(4x - 5) = 0

So,

Zero no. 1 (α) -

x + 1 = 0

=> x = -1

Zero no. 2 (β) -

4x - 5 = 0

=> 4x = 5

=> x = 5/4

____________________

Now,

Sum of zeroes (α+β) = -1 + 5/4

= (-4+5)/4

= 1/4

Product of zeroes (αβ) = (-1) × 5/4

= -5/4

____________________

To verify that,

Sum of zeroes = -b/a

= -(-1)/4

= 1/4

=> α + β = -b/a

Product of zeroes = c/a

= -5/4

=> αβ = c/a

We have found the these same value above. Hence, it has been verified.

Hope it helps.

#BeBrainly :-)

Answered by janvi816
1
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