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Answers
QUESTION :-
Find the zeroes of following quadratic polynomials and verify the relationship between the zeroes and coefficients.
4x² - x - 5
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SOLUTION :-
4x² - x - 5
In the standard form of quadratic polynomial (ax² + bx + c), here -
- a (coefficient of x²) = 4
- b (coefficient of x) = -1
- c = -5
_____________________
First of all, we have to find the zeroes of polynomial.
4x² - x - 5 = 0
=> 4x² + 4x - 5x - 5 = 0
=> 4x(x + 1) -5(x + 1) = 0
=> (x + 1)(4x - 5) = 0
So,
Zero no. 1 (α) -
x + 1 = 0
=> x = -1
Zero no. 2 (β) -
4x - 5 = 0
=> 4x = 5
=> x = 5/4
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Now,
Sum of zeroes (α+β) = -1 + 5/4
= (-4+5)/4
= 1/4
Product of zeroes (αβ) = (-1) × 5/4
= -5/4
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To verify that,
Sum of zeroes = -b/a
= -(-1)/4
= 1/4
=> α + β = -b/a
Product of zeroes = c/a
= -5/4
=> αβ = c/a
We have found the these same value above. Hence, it has been verified.
Hope it helps.
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