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Answer 1

Answer:

1:4

Explanation:

Capacitance is given by

C =A ε/d

where A represents the area of cross section of the plates and d represents the distance between the plates

Let the final capacitance by C'

C' = A₂ε/d₂

As radius is increased by $\sqrt{2}$ times, the area becomes twice as A= πr²

and its given that distance between the plates is halved

Hence C' = $\frac{2A\epsilon}{d/2}$

⇒ C' = $\frac{4A\epsilon}{d}$

⇒ C' = 4C

Which finally gives us that C:C' = 1:4

Hope it helps you.

Answer 2

Explanation:

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