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Answer 1

Explanation:

4s

2

−4s+1

Factorize the equation, we get(2s−1)(2s−1)

So, the value of 4s

2

−4s+1 is zero when 2s−1=0,2s−1=0, i.e., when s=

2

1

or s=

2

1

.

Therefore, the zeros of 4s

2

−4s+1 are

2

1

and

2

1

.

Now,

⇒Sum of zeroes =

2

1

+

2

1

=1=−

4

−4

=−

Coefficient of s

2

Coefficient of s

⇒Product of zeros =

2

1

×

2

1

=

4

1

=

4

1

=

Coefficient of s

2

Constant term

Answer 2

Answer:

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