Question

​​​​​​​​♤ Moderators

⭐ Branily star

❤️ other best user

Question <<<

please answer this question urgently fast answer

no spam

no spam

no spam​​​​​​​​​​​​​​​​​​​​​​​​

Answer 1

Question:

Five years hence, father's age will be three times the age of his son. Five years ago, father was seven times as old as his son. Find their present ages.​

Answer:

Son's present age = 10 years

Father's present age = 40 years

Step-by-step explanation:

Let the present age of father be x years and son's present age be y years

After five years :

father's age = (x + 5) years

son's age = (y + 5) years

Given, father's age = 3 × son's age

 x + 5 = 3(y + 5)

x + 5 = 3y + 15

x  = 3y + 15 - 5

x = 3y + 10 --- (1)

Five years ago,

father's age = (x - 5) years

son's age = (y - 5) years

Given, father's age = 7 × son's age

 x - 5 = 7(y - 5)

 x - 5 = 7y - 35

 7y - x = 35 - 5

 7y - x = 30

Substitute x = 3y + 10,

7y - (3y + 10) = 30

7y - 3y - 10 = 30

 4y - 10 = 30

 4y = 30 + 10

 4y = 40

  y = 40/4

 y = 10

∴ Son's present age = 10 years

Father's present age = 3(10) + 10 = 40 years

Answer 2

Step-by-step explanation:

Given :

Five years hence, father's age will be three times the age of his son.

Five years ago, father was seven times as old as his son.

To find :

Their present ages.

Solution :

Let the present ages of the Father and the Son be x and y years.

1st condition : [Hence/Future]

=> After 5 years man’s age = x + 5  

=> After 5 years ago son’s age = y + 5  

According to the question :

=> x + 5 = 3(y + 5)

=> x + 5 = 3y + 15

=> x - 3y = 10 -- (1)

2nd condition : [Ago/Past]

=> 5 years ago man’s age = x - 5

=> 5 years ago son’s age = y - 5  

According to the question :

=> x - 5 = 7(y - 5)

=> x - 7y = -30 -- (2)

Subtracting (2) from (1) :

=> x - 7y = -30

=> x - 3y = 10

• 4y = 40
• y = 10

Substitute the value of y in (1) :

=> x - 3y = 10

=> x - 3(10) = 10

=> x - 30 = 10

=> x = 40

Therefore :

Father's present age = 40 years.

Son’s present age = 10 years.

...ッ