Question

​​​​​​​​♤ Moderators ⭐ Branily star ❤️ other best user Question <<< please answer this question urgently fast answer no spam no spam no spam.


Five years hence, father's age will be three times the age of his son. Five years ago, father was seven times as old as his son. Find their present ages.​

Answer 1

Explanation:

Let the father present age =x years  and son present age =y years

According to the first condition

5 years later father will be (x+5) years old and son will be (y+5) years old.

⇒x+5=3(y+5)

⇒x+5=3y+15⇒x=3y+10....eq1

According to the second condition

5 years ago father was (x−5) years old and son was (y−5) years old.

⇒x−5=7(y−5)

⇒x−5=7y−35

⇒x−7y=−30....eq2

Put  the value of x from eq1

⇒3y+10−7y=−30⇒−4y=−40⇒y=10

Put y=10 in eq1

⇒x=3×10+10=40

 

Hence, Father present age =40 years

 Son present age =10 years