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Answer 1

Answer:

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Answer 2

ANSWER-;

Let M be the minimum molecular weight of the compound.

7% of the compound is sodium. It is equal to

$\frac{7}{100 } \times m = 0.07Mg$

sodium in 1 mole of compound.

At least, 1 mole of Na will be present in 1 mole of compound.1 mole of sodium weighs 23 g.

Thus, 0.07M=23

$m = \frac{23}{0.07} = 329g \mol$

Thus, the minimum molecular weight of the compound is 329 g/mol.