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Answers
1) a + ( b + c ) = ( a + b ) + c
Substitute the values,
->-25+ [20+ (-10) = [(-25) +20] + (-10)
Solve the RHS with brackets first,
Solve the LHS with brackets first,
→-25 + 10 = [(-25) +20] + (-10)
Add the integers in LHS,
→-15= [(-25) +20] + (-10)
->-15=(-5)+ (-10) Add the integers in RHS,
-> -15= -15
Comparing both sides,
LHS = RHS
.Thus, verified.
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2) a × (b + c) = a × b +a × c
Solution: Substitute the values,
->-25 x [20+ (-10)] = (-25) × 20 + (-25) × (-10)
Solve the LHS with brackets first,
->-25 x 10 = (-25) 20+ (-25) (-10)
Multiply the integers,
->250 = (-25) x 20 + (-25) × (-10)
Solve the RHS using BODMAS rule,
→> -250 = -500 + 250
Add the integers, ->-250 = -250
Comparing both sides,
+ LHS = RHS
Thus, verified.
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