History, asked by shivasinghmohan629, 18 days ago

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Answered by xxblackqueenxx37
7

 \: \: \: \huge{\underline{\underline{\textsf{\maltese{\red{answer}}}}}}

1) a + ( b + c ) = ( a + b ) + c

Substitute the values,

->-25+ [20+ (-10) = [(-25) +20] + (-10)

Solve the RHS with brackets first,

Solve the LHS with brackets first,

→-25 + 10 = [(-25) +20] + (-10)

Add the integers in LHS,

→-15= [(-25) +20] + (-10)

->-15=(-5)+ (-10) Add the integers in RHS,

-> -15= -15

Comparing both sides,

LHS = RHS

.Thus, verified.

__________________________

2) a × (b + c) = a × b +a × c

Solution: Substitute the values,

->-25 x [20+ (-10)] = (-25) × 20 + (-25) × (-10)

Solve the LHS with brackets first,

->-25 x 10 = (-25) 20+ (-25) (-10)

Multiply the integers,

->250 = (-25) x 20 + (-25) × (-10)

Solve the RHS using BODMAS rule,

→> -250 = -500 + 250

Add the integers, ->-250 = -250

Comparing both sides,

+ LHS = RHS

Thus, verified.

________________________

hope it was helpful to you

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