Question

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Solve This Question No 15th please.

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Answer 1

Given:-

• Height of the body is 20m
• Accelartion of body is 10m/s²

To find :-

• Velocity required to reach the ground
• Time required to reach the ground

SOLUTION :-

Since as it is dropped its initial velocity will be 0

• u = 0
• a = 10m/s²
• h = 10m (S= 10m)

From equations of motuion,

v² - u² = 2as

We can find velocity of a body

v² - 0 = 2(10)(10)

v² = 400

v = 20m/s

So, the velocity required to the body to strike the ground is 20m/s

From equations of motion Also we know,

v = u + at

20 = 0 + 10t

10t = 20

t = 2 seconds

Since it takes 2 seconds to the ground with velocity 20m/s

Know more some formulae

• S = ut + 1/2 at²
• S = vt - 1/2 at²
• S = v²-u²/2a
• u = v - at
• a = v² -u²/2s

Here ,

• S = Diatance
• a = accelartion
• t = time taken
• v = final velocity
• u = initial velocity