Question

#Mods challenge


On applying brakes a vehicles takes 10 seconds to stop ,if it was running at a speed of 40m/s then how long distance will
covered it before it stop


No spam!!!!
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Answer 1

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✏ǫᴜᴇsᴛɪᴏɴ

On applying brakes a vehicles takes 10 seconds to stop ,if it was running at a speed of 40m/s then how long distance will covered it before it stop??

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✏ ᴀɴsᴡᴇʀ

Given :

▪ Stopping time = 10s

▪ Initial velocity = 40mps

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To Find :

▪ Stopping distance of vehicle

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.Solution :

✒ First we have to find out retardation of vehicle after that we can calculate stopping distance with the help of kinematics formula.

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✳ Retardation of vehicle :▪ v = u + at▪ 0 = 40 - 10a▪ a = -40/10▪ a = -4m/s^2

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✒ Negative sign shows retardation.✴ Stopping distance of vehicle :

▪ v^2 - u^2 = 2as

▪ (0)^2 - (40)^2 = 2(-4)s

▪ 1600 = 8s

▪ s = 1600/8

▪ s = 200m

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Answer 2

The vehicle will cover 200 m distance before coming to stop.

Solution

Time take to stop(t) = 10 seconds.

Final speed(v) = 0 m/s

Initial speed(u)= 40 m/s

We will use 1st equation of motion to find acceleration :-

● v = u + at

⇒ 0 = 40 + a × 10

⇒ 0 = 40 + 10a

⇒ 10a = -40

⇒ a = -40/10

⇒ a = -4 m/s²

Now we will use 3rd equation of motion to find distance covered :-

● v² - u² = 2as

⇒ 0² - 40² = 2s × (-4)

⇒ 0 - 1600 = -8s

⇒ 1600 = 8s

⇒ s = 1600/8

⇒ s = 200 m

So distance covered by vehicle before coming to stop = 200 m.