Question

Modules of (1+2i)(1-3i) is
wrong answer will be reported ​

Answer 1

Answer:

hey here is your solution

pls mark it as brainliest

Step-by-step explanation:

$so \: here \: given \: complex \: number \: is\\ (1 + 2i)(1 - 3i) \\ \\ (1 + 2i)(1 - 3i) \\ \\ = 1 - 3i + 2i - 6i {}^{2} \\ \\ = 1 - 6( - 1) - i \\ \\ = 1 + 6 - i \\ \\ a + ib= 7 - i \\ \\ equating \: real \: and \: imaginary \: parts \\ we \: get \\ \\ a = 7 \\ b = - 1 \\ \\ so \: we \: know \: that \\ \\ |z| = \sqrt{a {}^{2} + b {}^{2} } \\ \\ = \sqrt{(7) {}^{2} + ( - 1) {}^{2} } \\ \\ = \sqrt{49 + 1} \\ \\ = \sqrt{50} \\ \\ |z| = 5 \sqrt{2}$