modulus and argument of z=-√3+i
Answers
Answered by
3
Answer:
z=−
3
+i
Modulus
∣z∣=
(−
3
)
2
+1
2
=
3+1
=2
∣z∣=2
Argument
θ=tan
−1
a
b
=tan
−1
−
3
1
=−30
∴θ=180−30=150
θ=150×
180
π
θ=
6
5π
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