Math, asked by mahimasuryavanshi190, 1 month ago

modulus of the vector 4i+3j-2k is ​

Answers

Answered by satendrakasana44841
0

Step-by-step explanation:

We have vector a = 4i + 3j + 2k 2 vector a = 8i + 6j + 4k and vector b = 3i + 2k = 3i + 0j + 2k ∴ vector|b x 2a| = |(i,j,k),(3,0,2),(8,6,4)| = i(0 - 12) - j(12 - 16) + k(18 - 0) = -12i + 4j + 18k ∴ vector|b x 2a| = √(122 + 42 + 182) = √484 = 2√121 = 22Read more on Sarthaks.com - https://www.sarthaks.com/594250/if-vector-a-4i-3j-2k-and-vector-b-3i-2k-then-find-vector-b-x-2a

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