Mohammad wants to pack 364 green candles and 448 red candles equally in a box so that no candle is left. What is the biggest possible number of boxes needed to pack all the candles?
Answers
Answer:
56 boxes are required to pack all the candles.
Step-by-step explanation:
In order to check the biggest number of possibles boxes and pack equal candles in each box, so that no candle is left.
We have to find the highest common factor of the number of Red and green candles.
∴The Factors of 364 and 448 are;
364=(13)(7)(4)
448=(16)(7)(4)
Hence, the HCF of 364 and 448 is (7)(4) = 28.
∴28 boxes for green candles which contains 13 candles in each box and
28 boxes for red candles which contains 16candles in each box.
Hence, 56 boxes are required to pack all the candles.
#SPJ3.
Answer:
Mohammad required 56 boxes to pack all the candles.
Step-by-step explanation:
Highest common factor of green(363) and red(448) candles
factors of 346 = 2* 2 * 7 * 13
factors of 448 = 2* 2 * 2 * 2 * 2 * 2* 7
common factors = 2 , 2 , 7
HCF of 364 and 448 = 2*2*7 = 28.
28 boxes for green candles, in which 13 candles are contained
28 boxes for red candles, in which 16 candles are contained
So total box = 28 + 28 = 56 boxes
Mohammad required 56 boxes to pack all the candles.
#SPJ3