Mohan and Sohan is a friend . Mohan write a linear equation in two variables 2x+3y = 5 and asked his friend to answer the following question with the help of equation .
A) What is the standard form of equation
i) 2x+3y-5=0
ii) 2x+3y+5= 0
iii) 2x=5-3y
iv) 3y= 5-2x
Answers
Answer:
2x=5-3y
Step-by-step explanation:
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Answer:
Given a person is standing at the junction of the below lines
2x−3y+4=0 ...(1)
3x+4y−5=0 ...(2)
Solving equation (1) and (2) ,we get
x=−
17
1
and y=
17
22
So, the person is standing at point (−
17
1
,
17
22
)
Given equation of path is
6x−7y+8=0 ...(3)
The person can reach this path in the least time if he walks along the perpendicular line to (3) from point (−
17
1
,
17
22
)
Slope of the line (3)=
7
6
∴ slope of the line perpendicular to line (3)=−
7
6
1
=−
6
7
The equation of the line passing through (−
17
1
,
17
22
) and having a slope of −
6
7
is given by
y−
17
22
=−
6
7
(x+
17
1
)
6(17y−22)=−7(17x+1)
102y−132=−119x−7
119x+102y=125
Hence, the path that person should follow is 119x+102y=125