Mohan and Sohan ran 2km race twice. Sohan
completed the first round 2 minutes earlier than
Mohan. In the second round, Mohan increased his
speed by 2 km / hr and Sohan reduced his speed
by 2 km /hr. Mohan finished 2 minute earlier than
Sohan. Find the speed of both in the first round.
Answers
Given : Mohan and Sohan ran 2km race twice. Sohan completed the first round 2 minutes earlier than Mohan.
In the second round, Mohan increased his speed by 2 km / hr and Sohan reduced his speed by 2 km /hr.
Mohan finished 2 minute earlier than Sohan.
To Find : the speed of both in the first round.
Solution:
Just by observing data we can conclude that difference in their speed difference is 2 km
1st round
Mohan = x km and Sohan = x + 2 km
and 2nd round
Mohan = x + 2 km and Sohan = x km
2/x - 2/(x + 2) = 2/60
=> 1/x - 1/(x + 2) = 1/60
=> (x + 2 - x)60 = x(x + 2)
=> 120 = x² + 2x
=> x² + 2x - 120 = 0
=> (x + 12)(x - 10) = 0
=> x = 10
speed of both in the first round.
Mohan Speed = 10 km
Sohan Speed = 12 km
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