Math, asked by cr66, 11 months ago

Mohan changed rupees 2 into 5 paise 20 paise and 50 paise coins if the number of 5 paise coins was the double of the number of 20 paise coin and the 50 paise coins paise coin 1/5 of 20 paise coins how many coins of each denomination did he get ​

Answers

Answered by Shaileshkrajan
11

Answer:

Step-by-step explanation:

Let the number of 50 paise coins be x

So

20 paise coins is 5 times the 50 paise coins

So 20 paise coins be 5x

Also

5 paise coins was double the 20 paise coins

So 5 paise coins is 5x*2=10x

Value of total number of coins = number of coins * value of coin

Value of 50 paise coins = 50*x paise

Value of 20 paise coins = 20*5x paise

Value of 5 paise coins = 5*10x paisx

Total value = 50x + 100x + 50x

=200x paise

Also tolal value is 2 rupees or 200 paise

So

200 paise = 200x paise

x =1

Substituting value

Number of 50 paise coins = x = 1

Number of 20 paise coins = 5x = 5

Number of 5 paise coins = 10x = 10

Answered by nidhitalwar1412
5

Answer:

Step-by-step explanation:

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