Math, asked by nishanthyadav2005, 28 days ago

Mohan deposits rs 500 in the first month ,rs 550 in the second month, rs 600 in the third month and so on find the total deposits at the end of 5 years

Answers

Answered by RKulavi2021
0

Answer:

Here, we are given first term i.e. 500 , then we have common difference of Rs. 50.

We can calculate number of months he deposited his money. According to the question, he deposited money for 5 years and in each month, so total months = 5 × 12 = 60 months -

So, now we have -

a = 500

d = 50

n = 60

=60/2 [2*500+(60 -1)50]

=30[2*500+(59)50]

=30[2*500+2950]

=30[1000+2950]

=30[3950]

=118500

Total money he deposited at the end of 5 years = Rs. 118500

Step-by-step explanation:

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