Question

Mohan found a box full of 43 coins while searching for treasure. He decides to count the coins by putting them into four piles.
In the first pile, he put some coins.
The second pile has two less than the first pile.
The third pile has 1 less than the last pile.
The last pile had twice as many as the second pile.
How many coins were in each pile?​

Answer 1

Coins in first pile=x
Coins in second pile=x-2
Coins in third pile=2(x-2)-1
Coins in fourth pile =2(x-2)

ATQ
x+(x-2)+2(x-2)-1+2(x-2)=43
x+x-2+2x-4-1+2x-4=43
6x-11=43
6x=43+11
6x=54
x=54/6
x=9
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Therefore,
Coins in first pile=9
Coins in second pile=7
Coins in third pile=13
Coins in forth pile=14