Math, asked by randomindian8182, 7 months ago

Mohan has 11 coins in his pocket. weights of these coins in grams are as

follows: 10, I l, 4, 12,5, 10,7,6,8, 9, 6.


58. What is the median weight?

(A)10 (B) 8. (c)7 (D) 9


59. The above data is to be arranged in to a frequency table with some suitably defined

class intervals. what is the frequency for the class interval ..9.5
- 11.5"? -


(A) 1 (B) 2 (c) 3 (D) 4​

Answers

Answered by nandini975
0

Answer:

median weight ⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️

10

Answered by smithasijotsl
0

Answer:

The median weight of the coins = 8

The frequency of the class interval 9.5 - 11.5 is 3

Step-by-step explanation:

Given,

Weight of 11 coins are 10, 11, 4, 12,5, 10,7,6,8, 9, 6.

To find,

a) The median weight of the coins

b) The frequency of the class interval 9.5 - 11.5

Solution:

Median of a data is the middle most value when  the values are arranged in the ascending order

Here, the values are 10, 11, 4, 12,5, 10,7,6,8, 9, 6.

When arranged in ascending order, 4,5,6,6,7,8,9,10,10,11,12

Since there are 11 observations, the middle most observation is the 6th term.

The sixth term in the set 4,5,6,6,7,8,9,10,10,11,12 is 8

∴ The median weight of the coins = 8

The correct answer is option (B) 8

b)  The frequency  for a class interval is the number of observations in that interval

The values 10, 10,11 lies in the class interval 9.5 - 11.5.

Hence there are 3 observations lies in the class interval 9.5 - 11.5.

The frequency of the class interval 9.5 - 11.5 is 3

The correct answer is option (c)3

#SPJ2

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