Question

Mohan is 8% taller than Ram and 8 Ankur is 20% shorter than Ram. By what percentage thom Ankur. entage is Mohan taller​

Answer 1

Answer: Mohan is taller than Ankur by 20%

Step-by-step explanation:

Consider the Heights be

M-Mohan;

R-Ram;

A-Ankur

Given M taller than R by 8%

and A shorter than R by 10%

Common term is R(Ram's height)

Assume height of Ram as 100.

R=100

M=100+8= 108

A=100-10=90

M>A by {[(M-A)/A]×100}%

{[(108-90)/90]×100}%

= (1/5)×100

= 20%

Therefore, Mohan is taller than Ankur by 20%.

Answer 2

Answer:

Mohan is $35\%$ taller than Ankur.

Step-by-step explanation:

Given: Mohan is $8\%$ taller than Ram and Ankur is $20\%$ shorter than Ram.

To Find: By what percentage is Mohan taller​ than Ankur.

Solution: Assume that the height of Ram is $100$ cm.

Then, the height of Mohan $= 100 + 8\%$ of $100$ cm    

                                             $\begin{aligned}& = 100 + \frac{8}{100} \times 100\end{aligned}$

                                             $= 100 + 8$

                                             $= 108$ cm

So, the height of Ankur $= 100-20\%$ of $100$ cm

                                       $\begin{aligned}& = 100 - \frac{20}{100} \times 100\end{aligned}$

                                       $= 100 - 20$

                                       $= 80$ cm

Now, the question is by what $\%$ is Mohan taller than Ankur.

Let  $x$ be the $\%.$

Then, Calculate $x$ by taking $100\%.$

$\begin{aligned}& \frac {x}{100} \times 80 = 108\end{aligned}$

         $\begin{aligned}&x = \frac{108}{80}\times 100\end{aligned}$

         $x = 1.35 \times 100$

            $= 135\%$

∴ Mohan's is $= 135\% - 100\%$

                     $= 35\%$ taller than Ankur.

Hence, Mohan is $35\%$ taller than Ankur.