Question

Mohan’s father is three times as old as Mohan. If the sum of their ages is 88, find their ages.

Answer 1

Answer:

LET

MOHANS AGE = x

MOHANS FATHERS AGE = 3x

= x + 3x = 88

= 4x = 88.

x = 88/4

x = 22.

VERIFICATION,

mohans age + mohans fathers age = 88.

mohans age = x = 22.

mohans fathers age = 3x = 66.

sum = 66 + 22 = 88.

Step-by-step explanation:

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Answer 2

$\underline{ \underline{\large\green\maltese \large{ \bf \red{Assumption:-}}}}$

$\sf \: \bull Let \: the \: Mohan's \: age \: be \: x$

$\sf \: \therefore \: Mohan's \: father's \: age \: will \: be \: 3x$

$\underline{ \underline{\large\blue\maltese \large{ \bf \green{Solution:-}}}}$

$\sf \: Sum \: of \: their \: ages = 88$

$\large↦$$\sf \: x + 3x = 88$

$\large↦$$\sf \: 4x = 88$

$\large↦$$\sf \: x = \cancel{\frac{88}{4}}$

$\large↦$$\sf \: x = 22$

❒$\red { \underline { \boxed{ \sf{Mohan's\: Age\: is\: 22 \:years }}}}$

Now,

$\sf \: Mohan's \: father's \: age = 3x$

$\quad\quad\quad\quad\quad\quad\quad\quad\quad$$\sf =3 × 22$$\quad$(x = 22)

$\quad\quad\quad\quad\quad\quad\quad\quad\quad$ $=\sf 66 \:years$

❒ $\pink { \underline { \boxed{ \sf{Mohan's \:father's \:age \;is \:66 \;years}}}}$

$\underline{ \underline{\large\purple\maltese \large{ \bf \orange{Verification:-}}}}$

$\sf Sum\: of \; their \: ages = 66+22$

$\quad\quad\quad\quad\quad\quad\quad\quad \sf = 88$

$\underline{ \underline{\frak\green{Verified}}}$