Math, asked by naira3547, 11 months ago

Mohan's mother is twice the age of Mohan 10 years earlier Mohan was 20 years younger than her mother find their present ages

Answers

Answered by emma3006
3

let the present age of Mohan be x

Then, his mother's present age = 2x

10 yrs before,

Mohan's age = x-10

his mother's age = 2x-10

A/q

(x-10) + 20 = 2x-10

x -10 +20 = 2x - 10

x + 10 = 2x -10

2x - x = 10 +10

x = 20

Mohan's present age = 20 yrs

his mother's present age = 2×20 = 40 yrs

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