Mohan's mother's present age is 6 times Mohan's present age. Mohan's age five
years from now will be one-third of his mother's present age. What are their present
ages?
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Answer:
A/Q 6x+5=x+25 6x-x=25-5 5x =20 x=20/5 x=4. Present Age of Mohan=x=4 years. Present Age of Mother=6x=6×4=24 years.
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Step-by-step explanation:
Let Mohan Present Age=X years
Then His Mother Age=6x years
5 years Later
Mohan Age=(X+5) years
His Mother Age=(6x+5) years
Mother Will be also 20 years Older than Mohan(X+5)
=(X+5+20)
=X+25
Mother Age will be also=(X+25) years
(6x+5) and (X+25) is Age of Mother after 5 years
Both Are same.
A/Q
6x+5=x+25
6x-x=25-5
5x=20
x=20/5
x=4
Present Age of Mohan=x=4 years
Present Age of Mother=6x=6×4=24 years
\boxed{\mathbf{\huge{Mohan=4\:years}}}
Mohan=4years
\boxed{\mathbf{\huge{Mother=24\:years}}}
Mother=24years
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