Math, asked by rb7608807, 7 months ago

Mohan's mother's present age is 6 times Mohan's present age. Mohan's age five
years from now will be one-third of his mother's present age. What are their present
ages?​

Answers

Answered by manjirimusale90511
2

Answer:

A/Q 6x+5=x+25 6x-x=25-5 5x =20 x=20/5 x=4. Present Age of Mohan=x=4 years. Present Age of Mother=6x=6×4=24 years.

Top answer · 11 votes

Answered by samridhibhargav32
34

Step-by-step explanation:

Let Mohan Present Age=X years

Then His Mother Age=6x years

5 years Later

Mohan Age=(X+5) years

His Mother Age=(6x+5) years

Mother Will be also 20 years Older than Mohan(X+5)

=(X+5+20)

=X+25

Mother Age will be also=(X+25) years

(6x+5) and (X+25) is Age of Mother after 5 years

Both Are same.

A/Q

6x+5=x+25

6x-x=25-5

5x=20

x=20/5

x=4

Present Age of Mohan=x=4 years

Present Age of Mother=6x=6×4=24 years

\boxed{\mathbf{\huge{Mohan=4\:years}}}

Mohan=4years

\boxed{\mathbf{\huge{Mother=24\:years}}}

Mother=24years

plz follow me and mark me as brainiest....

Similar questions