Mohan sells two kinds of product A and B. A pair of product A is sold at 30% profit and a pair of products B at 50% profit. Mohan calculated that if her sells 10% more producta of B than A, he would get oberall 45% profit. But he end up selling 50% more poducts of A than B. What is his overall profit now ?
Answers
Answer:
42.9%
Step-by-step explanation:
Let say Cost Price of Pair of product A = A
Selling Price of Pair of Product A = A + (30/100)A = 1.3A
Profit = 0.3A
Let say Cost Price of Pair of product B = B
Selling Price of Pair of Product B = B + (50/100)B = 1.5B
Profit = 0.5B
Let say X Product sold of A
10% more product of B Mean = 1.1X
Cost Price = AX +B(1.1X) = AX + 1.1BX
Profit = 0.3AX + 0.5B(1.1X) = 0.3AX + 0.55BX
Profit % = ((0.3AX + 0.55BX)/(AX + 1.1BX) ) * 100
=> 45 = ((0.3AX + 0.55BX)/(AX + 1.1BX) ) * 100
=> 45AX + 49.5BX = 30AX + 55BX
=> 15AX = 5.5BX
=> 15A = 5.5B
=> 30A = 11B
Let say Y products of B sold
Then 50% more product of A = 1.5Y
Cost Price = 1.5AY + BY
Profit = 1.5Y*0.3A + 0.5BY = 0.45AY + 0.5BY
Profit % = (0.45AY + 0.5BY)/(1.5AY + BY) * 100
=> Profit % = (45A + 50B)/(1.5A + B)
= (90A + 100B)/(3A + 2B) ( multiplying numerator & denominator by 2)
= (33B + 100B)/(1.1B + 2B) ( using 30A = 11B )
= 133B/3.1B
= 42.9%