Question

mohan travels at 20m/s from home to market and returns back at 25m/s.Find his average velocity for the entire journey​

Answer 1

Answer:

22.22m/s

Explanation:

let , the distance be d meter

Time taken when he go to market from home =

d/20 sec

Time taken when he go to home from market =

d/25 sec

Total distance = d+d = 2d mt.

Total time = d/20 + d/25 = 45d/500 sec

Then, average velocity = 2d/(45d/500) = 1000/45 = 200/9= 22.22 m/s.

Answer 2

Concept:

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time. It is mathematically expressed as, v = displacement/ time

Given:

Displacement of mohan from home to market = 20m/s

Displacement of mohan from market to home = 25 m/s

Find:

We need to determine the average velocity of mohan for the entire journey

Solution:

The pace at which an object's direction changes when it is travelling is referred to as its velocity and is measured by a particular unit of time and from a particular point of view.

In mathematics, it is written as v = displacement/time.

A shift in an object's position is referred to as "displacement." It has a magnitude and a direction, making it a vector quantity.

Given that Mohan travels from his home to the market at 20 m/s and back at 25 m/s.

From the above-given condition, it has been observed that the displacement of Mohan was zero since he returns to its original place.

displacement = 0

We have the formula, velocity = displacement/time

v = 0/time = 0

Thus, the average velocity for the entire journey is 0.

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