Question

Mohan walks 17m North-East and 8 m South. How far is he from his initial position?
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Answer 1

$hyp \( =17\;m\)Perpendicular \( =8\;m\)Base \( =\sqrt{{\left(17\right)}^{2}-{\left(8\right)}^{2}}\)\( =\sqrt{289-64}\)\( =\sqrt{225}\)\( =15\)Base \( =15\)Therefore, Mohan covers \( 15\;m\) from his starting point$