Mohan walks from his house at a speed of 5 kmph,
speed and reaches his office 10 minutes late. If his
speed had been 5 kmph he would have reached 10
minutes early. What is the distance to his office
from his house?
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Answer:
Let the actual time be 't'
and distance be x
Now according to first condition, we have
4
x
=t+
60
5
And according to Second condition, we have
5
x
=t−
60
10
60x=4t+20
60x=5t−50
Subtracting equation 1 from 2, we have
0=t−70
∴t=70
Putting the value of t we get x=5km
Step-by-step explanation:
Hope it helps
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