Math, asked by palakthakur1034, 11 months ago

Mohans mother is 20years older than him.10years ago she was 3 times as old as mohan was then find their present age

Answers

Answered by crystinia
41

Solution:-

Let Mohan's age be x years

So, Mother's age will be x + 20 years.

Before 10 years,

Mohan's age was x - 10 years.

Mother's age was (x + 20) - 10 years.

So The Equation will be:

3 (x - 10) = (x + 20) - 10

3x - 30 = x + 10

3x - x = 30 + 10

2x = 40

x = 40/2

x = 20

Therefore, Mohan's present age is 20 years.

Mother's age:

= 20 + 20

= 40 Years

Therefore, Mother's age is 40 years.

Answered by StarGazer001
11

Answer:-

Let Mohan's age be x years

So his mother's age will be x+20 years

Before 10 years,

Mohan's age was x-10 years

His mother's age was (x+20)-10 years

We will get =>

3(x-10)=(x+20)-10

3x-30=x-10

3x-x=30+10

2x=40

x=40÷2

x=20

Therefore Mohan's present age = 20 years

His mother's present age = 20+20 =40 years

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