Math, asked by Yashdevda, 1 year ago

mohans motheris 6times as old as mohan now.5 years later,she will be20 years older than mohan . What are their present ages?​

Answers

Answered by Anonymous
3

\huge{\mathfrak{anSweR \ :-}}

Let Mohan's age => "x" years

Mohan's mother's age => 6x

<u>5 Years Later :-</u>

Mohan's age => x + 5

Mohan's Mothers's age => 6x + 5

<b><u>According To Question :-</b></u>

6x + 5 = x + 5 + 20

6x - x = 25 - 5

5x = 20

x = \dfrac{20}{5}

x = 4

So, Their present Ages are :-

Mohan's present age => <u>4 Years</u>

Mohan's Mother's present age => 6 × 4 = <u>24 Years

Answered by Anonymous
0

Let Mohan Present Age=X years

Then His Mother Age=6x years

5 years Later

Mohan Age=(X+5) years

His Mother Age=(6x+5) years

Mother Will be also 20 years Older than Mohan(X+5)

=(X+5+20)

=X+25

Mother Age will be also=(X+25) years

(6x+5) and (X+25) is Age of Mother after 5 years

Both Are same.

A/Q

6x+5=x+25

6x-x=25-5

5x=20

x=20/5

x=4

Present Age of Mohan=x=4 years

Present Age of Mother=6x=6×4=24 years

\boxed{\bf{\huge{Mohan's\;age=4\;years}}}

\boxed{\bf{\huge{Mother's\;age=24\;years}}}

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