Question

mohini walks 1200m due east and 500m due north. how far is she from her starting point.

Answer 1

Answer:

The distance from her starting point is 1300m.

Step-by-step explanation:

Given that,

Mohini walks 1200m due east and 500m due north and we are required to find how far is she from her starting point (or) the distance covered.

We shall solve this using vector algebra.

Mohini walks 1200m due east hence her position vector is

$\vec r_{1}=1200\hat i$

Later she walks 500m due north hence her position vector is

$\vec r_{2}=500\hat j$

Hence her final position vector is

$\vec r=\vec r_{1}+\vec r_{2}=1200\hat i+500\hat j$

Now the distance from her starting point is the magnitude of the vector.

$d=|\vec r|=\sqrt{1200^2+500^2}=1300m$

Therefore,

The distance from her starting point is 1300m.

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Answer 2

Answer:

Her starting position is $1300$ meters away.

Explanation:

Her starting position is $1300$ meters away.

Given that,

Mohini travels $1200$ meters straight eastward and $500$ meters straight northward, and we must determine how far she has travelled overall. We'll use vector algebra to resolve this.

Since Mohini travels $1200$ meters due east, her position vector is

$r_{1} =1200m$

She then makes a $500$ meter northward stroll, so her position vector is

$r_{2} =500m$

Her final position vector is as a result.

$r=r_{1} +r_{2}$

  $=1200+500$

The magnitude of the vector is now determined by how far she is from her starting point.

$d=| r{}{} |=1200^{2} +500^{2}$

           $=1300m$

Her starting position is $1300$ meters away.

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