Math, asked by mohammedsulaiman9894, 4 months ago

mohini walks 1200m in east and 500m in north find how much far is she from her starting point

Answers

Answered by RitwikMahala
2

Answer:

1300 m

Step-by-step explanation:

by the pythagoras theorem. it will be square root of 1200^2+2500^2 which will be square root of 1690000 which os 1300 m

I hope this helps you.

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sorry if my pythagoras spelling is wrong :)

Answered by deepak33303
0

Answer:

1300m

Step-by-step explanation:

let she started to point A in East direction and reached at point B so the distance between A and B = 1200 m

now she started to point B to point C in North direction then distance between BC = 500 m

she make a right angle triangle

so AC^2=BC^2+AB^2

AC^2=(1200)^2+(500)^2

AC=√1440000+250000

AC=√1690000

AC =1300 M

she far away from starting point 1300m.

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