Question

Mohit borrowed 50000 from Rohit at 10% per annum simple interest and lent it to Keshav at the
rate but compounded annually, Find Mohit's gain after 2 years.​

Answer 1

Answer:

Rs 500

Step-by-step explanation:

SI=p x r x t/100

amount to be returned to rohit = 50000 + 50000 x 10 x 2/100 = 60000Rs

Now mohit lent it to keshav compounded anually

A=P(1+r/100)^n

A= 50000(1+10/100)^2

A=50000(11/10)^2

A=50000 x 11/10 x 11/10= 60500Rs

Therfore, mohit gains Rs 500 at the end of 2 years.

Answer 2

Answer:

500 mohit earn after 2 year

Given:-

• principle = 50000
• rate = 10%
• time = 2 years

To find :-

• mohits gain after 2 year

Solution:-

1st we will find simple interest

$s.i = \frac{p \times t \times r}{100} \\ \\ s.i = \frac{50000 \times 10 \times 2}{100} \\ \\ s.i =5 00 \times 10 \times 2 \\ \\ s.i = 10000 \\ \\ for \: \: amount \: \\ \\ amount = s.i + p \\ amount = 10000 + 50000 = 60000$

• mohit had to paid 60000 to rohit after 2 years
• at the basis of simple interest

now for compount interest

• principle = 50000
• rate = 10%
• time = 2

$amount = p \times ( { \frac{r}{100} + 1) }^{n} \\ \\ \: \: \: \: \: \: \: \: = 50000 \times ( { \frac{10}{100} + 1) }^{2} \\ \\ \: \: \: \: \: \: \: \: \: = 50000 \times \frac{110}{100} \times \frac{110}{100} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: = 500 \times 11 \times 11 \\ \\ amount = 500 \times 121 \\ \\ amount = 60500$

• keshav had to pay 60500 to mohit at the basis of compound interes

there for

mohit earn 500 after 2 year