Question

mohit bought 5/7 kg of rice and rohan bought 7/9 kg of rice who bought more rice and by how much​

Answer 1

Answer:

You are good in studies i think

Answer 2

Answer:

$\huge {\underline {\underline {\fbox{ANSWER}}}}$

=> Amount of rice bought by Mohit

$= \frac{5}{7}$

=> Amount of Rice bought by Rohan

$= \frac{7}{9}$

=> Difference

$= \frac{5}{7} - \frac{7}{9}$

(Take out the L.C.M. of the denominators i.e. 7 & 9 = 63)

(Now, 7 × 9 = 63, so we will multiply the numerator with 9 also i.e. = 5 × 9 = 45. We will do the same for the second number. 9 × 7 = 63, so we will multiply the numerator with 7 also i.e. = 7 × 7 = 49)

$\frac{49}{63} - \frac{47}{63}$

$= \frac{3}{63}$

$= \frac{1}{21}$

Hence, Rohan bought more by

$\frac{1}{21}$

Explanation:

HOPE THIS HELPS YOU!!