Question

Mohit bought two t.v.set for Rs.42500 he sold one at a loss of 10%and other at a profit of 10% selling price of each t.v.is same determine cost price of each sets.

Answer 1

let the cost price of first tv set be = Rs x
and the cost price of second tv set = 42,500-x
Selling price of first tv set = x(100-10/100)
= 9x/10
S.P of second tv set=(42,500-x)(100+10/100)
=(42,500-x) (11/10)
scince the selling price of both tv sets are equal, hence
9x/10=(42,500-x)(11/10)
9x/10=4,67,500-11x/10
9x=4,67,500-11x
11x+9x=4,67,500
20x=4,67,500
x=4,67,500/20
x=23,375
thus cost price of first tv set is Rs 23,375
and the cost price of second tv set = 42500-x
=42,500-23,375
=Rs19,125