Question

mohit deposits a sum of 12000 in the bank at a certain rate of intrest for 2 years and earns an intrest of rupees 900 how much intrest would be earned for a deposit of 15000 for the same rate of intrest​

Answer 1

Answer:

Interest = 1125

Step-by-step explanation:

Interest = P × R/100

900= 12000 × R/100

Rate= 7.5%

Interest = P× R/100

Interest = 15000× 7.5/100

Interest = 1125

Answer 2

Given:

Principal amount, $P_{1}$ = 12000

Principal amount, $P_{2}$ = 15000

Time = 2 years

Interest = Rs 900

To find:

Rate of interest for depositing Rs 12000 and interest earned for Rs 15000 for the same interest rate.

Solution:

Let P be the principal amount, R be the rate of interest and T be the time in years, then, simple interest (S.I) is calculated as:

$S.I=\frac{P*R*T}{100}$

Since, we are asked to find rate of interest R,

$R=\frac{S.I*100}{P*T}$

$R=\frac{900*100}{12000*2}$

$R=3.75$

Interest earned for depositing Rs 15000 at same rate,

$S.I=\frac{15000*3.75*2}{100}$

$S.I=1125$

For a sum of 12000 to be deposited in the bank, the rate of interest for 2 years will be 3.75.

Rs 1125 will be earned as interest if Rs 15000 is deposited for the same rate.