Question

mohit invested a certain sum in three different schemes A,B and C with rates of interest 10% p.a.,12% p.a. and 15% p.a. respectively. If the total interest accrued in 1 year is rs 3200 and the amount invested in scheme C was 150% of the amount invested in scheme A and 240% of the amount invested in scheme B , then what is the amount invested in scheme B ?



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Answer 1

Answer:

5000 -/Rs

Step-by-step explanation:

ATQ

[(a x 10 x 1)/100] + [(b x 12 x 1)/100] + [(c x 15 x 1)/100] = 3200

⇒ 10a + 12b + 15x = 320000 .....(i)

Now, c = 240% of b = 12b/5 ....(ii)

and c = 150% of a = 3a/2

⇒ a = 2c/3 = (2/3 x 12/5) b = 8b/5 .....(iii)

From Eqs. (i), (ii) and (iii), we get

16b + 12b + 36b = 320000

⇒ 64b = 320000

∴ b = 5000

∴ Sum invested in scheme Q = ₹ 5000

Answer 2

Answer:

5000

Step-by-step explanation:

let investment in A = 100%

C = 150% of 100% = 150%

investment in B = 100×150/240 = 62.5%

their investment ratio

= 100 : 62.5 : 150 = 8 : 5 : 12

let constant ratio be 'x'

total interest accrued = 3200

1/100 *( 80x + 60x + 180x) = 3200 => x = 1000

amount invested in scheme B

5x = 5(1000) = Rs 5000