Question

Mohit is 4 years younger than Sonu. Three years ago Sonu's age was twice the age
of Mohit. Find their present ages.​

Answer 1

Answer:

Step-by-step explanation:

let sonu ' s present  age =x years

∴ mohit's  present age=(x-4)years

three years ago

sonu's age=2(mohit's age)

i.e.   x= 2(x-4)

 ⇒   x=2 x-8

⇒    x-2 x= -8

⇒   -x= -8

⇒  x=8  

so, sonu's present age= 8 years

and mohit's  present age=4 years