Question

Mohit is a professional driver and loves to go on long rides. One day during his journey a dog suddenly appears in front of his car at 6m away due to which he applies break and velocity of car drops to zero from 3m/s by covering a distance of 5m. the weight of car is 700kg, the retarding force applied due to breaks will be ?

Answer 1

Answer:

630 Newton is the retarding force.

Explanation:

We have, u=3m/s, v=0, s=5m

So, using third equation of motion,

2as = v^2 - u^2

⇒ 2a × 5 = 0-3^2

⇒ 10a = -9

⇒ a = -9/10

So, the retardation is 9/10 m/s^2

Hence, Retarding force = mass × acceleration = 700kg×9/10 = 630 Newton