mohit is thinking is two no. their hcf is 6 and LCM is 36 one of them is 12 find the another
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one number =a =12
let the second number =b
hcf =6
lcm = 36
a*b = hcf*lcm
b= (hcf*lcm)/a
= 6*36/12
= 6*3
=18
second number = b=18
let the second number =b
hcf =6
lcm = 36
a*b = hcf*lcm
b= (hcf*lcm)/a
= 6*36/12
= 6*3
=18
second number = b=18
Answered by
0
we know that
1st no * 2nd no= LCM*HCF ( OF TWO NUMBERS)
LET first no is X and 2nd is Y so
X*Y = LCM*HCF
12*Y=6*36
Y= 6*36/12
= 6*3
=18
2nd number = Y=18
1st no * 2nd no= LCM*HCF ( OF TWO NUMBERS)
LET first no is X and 2nd is Y so
X*Y = LCM*HCF
12*Y=6*36
Y= 6*36/12
= 6*3
=18
2nd number = Y=18
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