Question

Mohit is twice as old as Ronit. If four years are added to Mohit's age and six years are subtracted from
Ronit's age, then Mohit's age will be four times Ronit's age.

Answer 1

Answer:

Let assume Mohit’s current age is X and his son’s current age is Y.

Now a year ago Mohit was four times his son’s age.

Mohit’s age a year ago = X-1 years

His son’s Y-1 years

Thus,

(X-1) = 4(Y-1)

OR X-1= 4Y-4

OR X-4Y= -3 ……(EQ.1)

AFTER SIX YEARS

MOHIT WILL BE X+6 AND HIS SON WILL BE Y+6 YEARS OLD.

ACCORDING TO QUE.

X+6 = 2(Y+6)+9 …….( In six years his age will be 9 more than twice his son's age)

Or X+6=2Y+12+9

OR X+6=2Y+21

OR X-2Y=15…… (EQ.2)

NOW BY EQ. NO.1 X=4Y-3

PUTTING THIS IN EQ 2

4Y-3–2Y=15

OR 2Y=18

OR Y=9 YEARS (SONS AGE)

SO X=4Y-3

X=33 YEARS MOHITS AGE