Question

mohit makes 8 full rounds of a rectangle field with length 120m and breadth 75m john make 10 full rounds of a square field with each side 100m find who covers larger distance and by how much​

Answer 1

Answer:

880 m

Step-by-step explanation:

Length of the rectangular field = 120 m

Breadth of the rectangular field = 75 m

∴ Distance covered in one round (perimeter) = 2(1 + b) = 2(120 + 75) = 390 m

Hence, distance covered in 8 rounds = 390 x 8 m = 3120 m

John Side of the field = 100 m

∴ Distance covered in one round = 4 x a = 4 x 100 = 400 m

Hence, Distance covered in 10 rounds = 400 x 10 m = 400 m

John a covers greater distance then Mohit by = (4000-3120) m = 880 m

Answer 2

Answer:

John

Step-by-step explanation:

Mohit`s Rectangle has dimensions : 120m x 75m

     Perimeter =  2(120+75)

                       ==390

Rounds taken = 8

    390*8 = 3,120 m

Therefore Mohit travelled an Perimeter of 3,120 m

John`s rectangle has dimensions : 100 x 100

     Perimeter    = 100*4

                          == 400m

Rounds taken   = 10

         Perimeter = 10*400

                           ==4000 m

John`s Perimeter - Mohit`s Perimeter

4,000  - 3,120 = 880m

Therefore John travelled more by 880m