Mohit run around a Park which is 140 m long and 120 m wide , if he took 5 round , what distance did he conver
Answers
Answer:
1,300
Step-by-step explanation:
120+140=260
260*5=1,300
GivEn:
- Length of park = 140m
- Breadth of park = 120m
- Mohit take 5 round of that park.
To finD:
- Distance covered by Mohit oh he take 5 round.
Solution:
Here, we know that length and breadth of park is 140m and 120m respectively. Now, we can say that this park is in the form of rectangle.
Now,
Distance covered by mohit = 5× perimeter of rectangle.
Therefore, at first we will find the perimeter of rectangle and then multiply it with 5.
Finding perimeter of rectangle :
We have given that length and breadth of rectangle is 140m and 120m respectively.
We know that :
Perimeter of rectangle = 2( Length + Breadth)
Substituting values in formula:
Perimeter of rectangle = 2( Length + Breadth)
=> Perimeter of rectangle = 2( 140 + 120)
=> Perimeter of rectangle = 2 × 260
=> Perimeter of rectangle = 520m
∴ Perimeter of rectangle = 520m
Finding distance covered by Mohit:
We know that mohit run 5 times in park. So the distance covered by mohit will be equal to 5 times the perimeter of rectangle.
=> Distance covered mohit = 5( perimeter of rectangle)
=> Distance covered by mohit = 5 ( 520)
=> Distance covered by mohit = 2600m
∴ Distance covered by mohit in 5 round = 2600m.
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