mohit will write such a number that 4 times of the sum total of the two digits will be 3 more of the number and if the digits are reversed the number will be increase by 18 calculate the number
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EXPLANATION.
mohit will write such a number that 4 times of
the sum total of the two digit will be 3 more
of the number and if the digit are reversed
the number will increased by 18
TO FIND THE NUMBER.
according to the question,
Let the unit digit be = x
Let the tens digit be = y
original number = 10x + y
reversing number = 10y + x
According to the question,
case = 1
=> 4 ( x + y) = 3 + [ 10x + y ]
=> 4x + 4y = 3 + 10x + y
=> 6x - 3y + 3 = 0
=> 2x - y + 1 = 0 ......(1)
according to the question,
Case = 2
=> 10y + x = 10x + y + 18
=> 9y - 9x = 18
=> y - x = 2 ......(2)
From equation (1) and (2) we get,
=> x = 1
put the value of x = 1 in equation (1)
we get,
=> 2(1) - y + 1 = 0
=> y = 3
Therefore,
Number are = 10x + y
10(1) + 3 = 13
Number are = 13
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